Problem Statement:
You are given BST and a kth element in the given tree.
Then you need to give the kth smallest element.
Solution
Solution is very simple.
We will take in-order traversal and store it an array.
Then we take the kth smallest element.
Solution in C++
#include<iostream>
#include<vector>
#include<string>
#include<set>
using namespace std;
struct Node
{
int data;
struct Node *left, *right;
};
Node *get_new_node(int item)
{
Node *temp = new Node;
temp->data = item;
temp->left = temp->right = NULL;
return temp;
}
Node* insert_into_bst(Node* node, int data)
{
if (node == NULL) return get_new_node(data);
if (data < node->data)
node->left = insert_into_bst(node->left, data);
else if (data > node->data)
node->right = insert_into_bst(node->right, data);
return node;
}
void print_inorder(Node* Node)
{
if (Node == NULL)
return;
print_inorder(Node->left);
cout<<" "<<Node->data;
print_inorder(Node->right);
}
void inorder(Node* root, vector<int> &res)
{
if(!root)
return;
inorder(root->left, res);
res.push_back(root->data);
inorder(root->right,res);
}
int kthSmallest(Node* root, int k)
{
if(!root)
return -1;
vector<int> arr;
inorder(root, arr);
return arr[k-1];
}
int main()
{
Node *root_1 = NULL;
root_1 = insert_into_bst(root_1, 1);
insert_into_bst(root_1, 2);
insert_into_bst(root_1, 3);
insert_into_bst(root_1, 4);
insert_into_bst(root_1, 5);
cout<<"The kth smallest element is "<< kthSmallest(root_1, 2)<<endl;
return 0;
}
Output:
The kth smallest element is 2